Question

by how much does 5/7/10 exceed 5/7/-10​

Answer 1

$\dfrac{1}{7}$ exceed by $\dfrac{5}{\dfrac{7}{-10}}$.

Step-by-step explanation:

We have,

$\dfrac{5}{\dfrac{7}{10}}$ exceed $\dfrac{5}{\dfrac{7}{-10}}$

⇒$\dfrac{5}{70} -(-\dfrac{5}{70})$

⇒ $\dfrac{5}{70} +\dfrac{5}{70}$

⇒$\dfrac{5+5}{70}=\dfrac{10}{70}$

$=\dfrac{1}{7}$

Hence, $\dfrac{1}{7}$ exceed by $\dfrac{5}{\dfrac{7}{-10}}$.

Answer 2

the answer is 7~3/14=101/14