Question

By increasing the price of book by Rs. 10. A person can buy 10 less books for Rs. 1200. Find the original list price of the book.

Answer 1

$\textbf{Answer:}$

Let the price of book be x,

No. Of books bought in 1200 rupes,

$= \frac{1200}{x}$

When the list price is increased by 10rs

=(x+10)

Now,

No. Of books bought in 1200 rupees

$= \frac{1200}{x + 10}$

If the person buys 10 less books,

$= > \frac{1200}{x} - \frac{1200}{x + 10} = 10 \\ \\ = > \frac{1200(x + 10) - 1200x}{x(x + 10)} = 10 \\ \\ = > 1200x + 12000 - 1200x = 10 {x}^{2} + 100x \\ \\ = > 10 {x}^{2} + 100x - 12000 = 0 \\ \\ = > {x}^{2} + 10x - 1200 = 0 \\ \\ = > {x}^{2} + 40x - 30x - 1200 = 0 \\ \\ = > x(x + 40) - 30(x + 40) = 0 \\ \\ = > (x - 30)(x + 40) = 0 \\ \\ = > x = 30 \: or \: x \: = - 40 \\ \\ = > x = 30$

Rate of any product cannot be negative

$\textbf{Hope it helps you!}$

Answer 2

Answer:

Hope its help

Mark it as Brainliest

:)

:)

:)