Question

By observing the digit at ones place tell which of the following can be perfect square 1026,1022,1024,1027

Answer 1

Answer : $\bold{Perfect \: Square \: = \: 1024}$



Explanation -



No square numbers ends with 2, 3, 7 or 8.


The number of zeros at the end of a square number is always even.


A number ending with an odd number of zeros is never a perfect square.


1026 is not a perfect square.


_______________________________


√1026 = 32.03

√1022 = 31.96

√1024 = 32

√1027 = 32.04



Hence :


${32}^{2} = 1024$



Answer : $\bold{Perfect \: Square \: = \: 1024}$

Answer 2

Step-by-step explanation:

Answer : \bold{Perfect \: Square \: = \: 1024} PerfectSquare=1024

Explanation -

No square numbers ends with 2, 3, 7 or 8.

The number of zeros at the end of a square number is always even.

A number ending with an odd number of zeros is never a perfect square.

1026 is not a perfect square.

_______________________________

√1026 = 32.03

√1022 = 31.96

√1024 = 32

√1027 = 32.04

Hence :

{32}^{2} = 102432

2

=1024

Answer : \bold{Perfect \: Square \: = \: 1024} PerfectSquare=1024