Question

By passing .1 faraday of electricity through fused nacl. The amount of chlorine liberated is

Answer 1

On passing 0.1F of electricity in NaCl,

the amt of chloride liberated = 35.45*0.1 =3.545

hence it is option C

Answer 2

Answer:

Explanation:W of cl2 =no.of faradays (into).35.5

=0.1(into).35.5gm

=3.545grams