Question

by prime factorisation
$11 {x}^{2} + 108x - 20 = 0$
​

Answer 1

Answer:

(x+10)(11x-2)

Step-by-step explanation:

$11 {x}^{2} + 108x - 20 = 0$

$= 11{x}^{2} + 110x - 2x - 20$

$= 11x(x + 10) - 2(x + 10)$

$= (x + 10)(11x - 2)$

Answer 2

$\sf{11 {x}^{2} + 108x - 20 = 0} \\ \\ \sf{11{x}^{2} + (110 - 2)x - 20 = 0 } \\ \\ \sf{11 {x}^{2} + 110x - 2x - 20 = 0 } \\ \\ \sf{11x(x + 10) - 2(x + 10) = 0} \\ \\ \sf{(x + 10)(11x - 2) = 0} \\ \\ \bf{(x + 10) = 0} \\ \rightarrow \boxed{\sf{x = - 10}} \\ \\ \bf{(11x - 2) = 0} \\ \rightarrow \sf{11x = 2} \\ \rightarrow \boxed{\sf{x = \dfrac{2}{11} }}$