Question

By reducing the selling price of an article by ₹100 , a gain of 10% turns into a loss of 10% . Find the original selling price of that article

Answer 1

cp =100 nd 10% gain so sp=110
cp=100 nd loss=10% so sp=90
11/10x-100=9/10x
11x/10-9x/10=100
2x/10=100
x=500
so original sp value =11

so 11=11×500=rs.5500

Answer 2

Answer:

Let Rs x be the cost price and Rsy be the the selling price of the

article.

we know that

Gain%=(

C.P

Gain×100

)

∴5%=(y−x)×

x

100

⇒x=20(y−x)

⇒x=20y−20x

⇒x+20x=20y

⇒21x=20y

⇒y=

20

21x

When the selling price of the article is reduce by Rs50 then the

new selling price of article =Rs(

20

21x

−50)

we know that

Loss%=(

C.P

loss×100

)

5=[

x

x−{

20

21x

−50}

]×100

⇒x={

20

x−21x

+50}×20

⇒x=[

20

{20x−21x+1000}

]×20

⇒x=−x+1000

⇒x+x=1000

⇒2x=1000

So, the cost price of article is Rs500

The original selling price y=

20

21x

=

20

21×500

y=525

The original selling price is Rs 525