Question

Please also answer this ASAP

Answer 1

Answer:

$Hello!$

∠3 = 50°   ( given )

∠1 = ∠3 = 50°  ( corresponding angles are equal )

∠2 = ∠1 = 50°   ( vertically opposite angles are equal )

∠4 = ∠3 = 50°  ( vertically opposite angles are equal )

∠4 + ∠5 = 180°  ( linear pair )

∠5 = 180 - 50

      = 130°

∠3 +∠6 = 180° ( linear pair )

∠6 = 180- 50

      =  130°

∠7 = ∠5 = 130°  ( corresponding angles are equal )

∠8 = ∠6 = 130° ( corresponding angles are equal )

Answer 2

Answer:

∠2=∠1=50°  [alternate angle]

∠3=∠1=50°[corresponding angle]

∠2=∠4=50°[corresponding angle]

∠3+∠5=180°[angle sum property]

⇒∠5=130°

∠5=∠8=130°[alternate angle]

∠8=∠7=130°[vertically opposite angle]

∠5=∠6=130°&∠3=∠4=50°[vertically opposite angle]

therefore;

∠1=50°

∠2=50°

∠3=50°

∠4=50°

∠5=130°

∠6=130°

∠7=130°

∠8=130°

hope it helps u plz mark brainliest...