Question

By remainder theorem find the remainder when p(x) is divided by g(x)? p(x)=x³-2x²-4x-1,g(x)=x+1
Please write in copy then attach​

Answer 1

➤ Answer

• The remainder when we divide x³ - 2x² - 4x - 1 by x + 1 = 0.

➤ To Find

• The remainder if x³ - 2x² - 4x - 1 is divided by x + 1.

➤ Step By Step Explanation

Given that p(x) = x³ - 2x² - 4x -1 and g(x) = x + 1

We need to find the remainder using remainder theorem.

So let's do it !!

Value of x.

➠ x + 1 = 0

➠ x = ( -1 )

By substituting the value of x.

$\longmapsto\tt {x}^{3} - 2 {x}^{2} - 4x - 1 \\ \\\longmapsto\tt {( - 1)}^{3} - 2 { (- 1)}^{2} - 4( - 1) - 1 \\ \\ \longmapsto\tt - 1 - 2(1) + 4 - 1 \\ \\\longmapsto\tt - 1 - 2 + 4 - 1 \\ \\ \longmapsto\tt (-4) + 4 \\ \\\longmapsto{\sf{\green{0}}}$

Therefore the remainder = 0

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➤ Extra Information

• Polynomial - An algebraic expressions in which the variable involved having non negative integral power is known as polynomial.

• Constant - A symbol having a fixed numerical value is known as constant.

• Variable - A symbol which may be assigned different numerical values is known as a variable.

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