Question

by remainder therom find the remainder of x³+3x²+3x+1divided by 5+2x​

Answer 1

(v) We have (p(x) = x3 + 3x2 + 3x + 1 and zero of 5 + 2x is

$( - 5 \div 2)$

Answer 2

x = -2/5
Put this value in equation
As 5+2x is a sector therefore on dividing it by the above question will give a zero therefore
(-2/5)^3 + 3(-2/5)^2 +3(-2/5) = 0
(-8/125) + (12/75) - (6/5) = 0
LCM of 125,75,5 = 1625