Question

by selling 18 oranges a vendor loses the selling price of 2 oranges find his loss percent.​

Answer 1

Let, the CP of an orange be 'x'

The CP of 2 oranges = 2x

The CP of 18 oranges = 18x

The SP of 18 oranges = (18x-2x)

                                    = 16x

Loss = (18x- 16x)

        = 2x

So, loss % = (2x/18x)*100

                 = (100/9)

                 = 11+(1/9)%

(Ans): 11 whole of 1/9 %

Answer 2

$\huge \purple{ \underline{ \boxed{ \red{ \mathbb{ANSWER : }}}}}$

$\red{ \textsf{Loss percentage = \orange{10\% }}}$

$\huge \purple{ \underline{ \boxed{ \red{ \mathbb{EXPLANATION : }}}}}$

$\red{ \textsf{Let x be the price of an orange . }}$

$\green{ \mathbb{ACCORDING \: TO \: QUESTION :}}$

$\red { \textsf{Cost Price = 18x+2x = 20x}}$

$\red{ \textsf{Selling Price=18x}}$

$\red{\mathsf{Loss \: Percentage = \frac{Cost Price - Selling Price }{Cost Price} \times 100 }}$

$\red{\mathsf{Loss \: Percentage = \frac{2 \cancel{x}}{20 \cancel{x}} \times 100}}$

$\red{\mathsf{Loss \: Percentage = \frac{100}{10} }}$

$\red{ \colorbox{yellow}{\boxed{\mathsf{Loss \: Percentage = 10\%}}}}$