by selling 180 orange A man lost the SP of 20 Orange find his loss percent had he purchase them for rupees 270 what would have been the SP of one orange
Answers
Answered by
15
let SP of 1 orange=SP
and, CP of 1 orange=CP
then loss on 1 orange=CP-SP
a/c to the question
Total loss on 180 oranges=SP of 20 oranges
i.e 180(CP-SP)=20 SP
or, SP/CP=9/8
or, (SP-CP)/CP=1/8
Loss%=(SP-CP)/CP*100%=12.5%
Now, if CP=Rs 270
SP=87.5% of 270=Rs 236.25
and, CP of 1 orange=CP
then loss on 1 orange=CP-SP
a/c to the question
Total loss on 180 oranges=SP of 20 oranges
i.e 180(CP-SP)=20 SP
or, SP/CP=9/8
or, (SP-CP)/CP=1/8
Loss%=(SP-CP)/CP*100%=12.5%
Now, if CP=Rs 270
SP=87.5% of 270=Rs 236.25
Answered by
8
Step-by-steLet
Let cost of one orange =1 rupee
So sp of 20 oranges = 20 rupees and sp of 180 oranges =180 rupees.
Loss = sp of 20 oranges =20 rupees. After all solution 10 % loss and sp of one orange = 1.35 rupees. After solution has been given below.
Attachments:
Similar questions