By selling 40orange for rupee7,a vendor gained 5% . How many for a rupee did he buy ?
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Answered by
1
c.p of 1 orange =7
c.p of 40 oranges=40×7=280
gain=5%
s.p={(100+5)/100}280
=(105/100)280
=2940/10
=294
the required s.p=294
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Answered by
4
Answer:
Sp of 1 orange = 700/40=70/4=17.5
Paise
c.p=17.5x100/105=16.67 Ps
No. of orange for one rupee =
100/16.67=6
6oranges for I rupee Ans
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