Physics, asked by adhil285, 1 year ago

Derive an expression for excess pressure inside a bubble drop.

Answers

Answered by Anomi
2
Pⁿ = P°–4S/R , where Pⁿ represents excess pressure inside soap bubble, 'P°' is the atmospheric pressure , 'S' represents Surface tension of the surface of soap bubble and 'R' is the radius of miniscous formed by soap bubble , hope it helped mark brainliest

adhil285: how is it derived??
Anomi: you need the derivation?
adhil285: yep
adhil285: class 11
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