by selling 45 oranges for rupees 160, a woman losess 20%. How many oranges should she sell for rupees 112 to gain 20% on the whole?
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Let CP be Rs x
case of loss,
SP of 1 orange = Rs 160/45
Loss = 20%
⇒SP = CP - Loss
= x - 20% of x = x - 0.2x = 0.8x
⇒160/45 = 0.8x
⇒x = Rs 40/9
case of gain,
Let the number of orange be y
SP of 1 orange = Rs 112/y
SP = CP + gain
= x + 20% of x = x +0.2x = 1.2x = 1.2×(40/9)
⇒112/y = 1.2×(40/9)
⇒y = 21
so, 21 oranges should she sell for rupees 112 to gain 20% on the whole.
case of loss,
SP of 1 orange = Rs 160/45
Loss = 20%
⇒SP = CP - Loss
= x - 20% of x = x - 0.2x = 0.8x
⇒160/45 = 0.8x
⇒x = Rs 40/9
case of gain,
Let the number of orange be y
SP of 1 orange = Rs 112/y
SP = CP + gain
= x + 20% of x = x +0.2x = 1.2x = 1.2×(40/9)
⇒112/y = 1.2×(40/9)
⇒y = 21
so, 21 oranges should she sell for rupees 112 to gain 20% on the whole.
Answered by
0
Answer:
But you didn't have to cut me off
Make out like it never happened and that we were nothing (aah-ooh)
Step-by-step explanation:
But you didn't have to cut me off
Make out like it never happened and that we were nothing (aah-ooh)
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