x2+3x-4=0 find this urgently
Anonymous:
what to find
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Answered by
2
root 1 = - b +√( b² - 4ac) /2a
= -3 +√(9-(-16))/2
= -3+ 5/2
= 1
root 2 = - b+ √( b² - 4ac) /2a
= -3 - 5 / 2
= -4
= -3 +√(9-(-16))/2
= -3+ 5/2
= 1
root 2 = - b+ √( b² - 4ac) /2a
= -3 - 5 / 2
= -4
no u were wrong at that time
we can edit an answer only for sometime after giving the answer
like for 20 min
(;
later on, u can't
ok dont bark now
Okay, but mind it i am reporting ur comment
shut up now
Okay, cool down sly person
keep going on
Answered by
1
hope it helps .............
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the formula is ±b + √b² - 4ac /2a NOT ±b + √b² + 4ac / 2a...U are wrong !!
First of all, ur image is not clear
Oops sorry! my mistake
formula is -b+-root b squre- 4ac. this is correct formula
thanks for admitting ur fault
try and then answer
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