Math, asked by kaandekarsowmya1288, 1 year ago

By selling a purse for rupees 250, ranjan loses one-sixth of what it cost her. Find 1) the cost price of the purse 2) her loss percentage.

Answers

Answered by Anonymous
273
1) Let the cost price of the purse be ₹x. Then,
Loss = 1/6 of ₹x
= ₹x/6
Cost Price = Selling Price + Loss
x = 250 + x/6
x - x/6 = 250
6x - x/6 = 250
5x/6 = 250
x = 250×6/5
x = 300
Hence, the cost price of the purse is ₹300.

2) Loss = Cost Price - Selling Price
= ₹(300-250)
= ₹50
Loss % = Loss/Cost Price × 100
= 50/300 × 100
= 50/3 %
= 16 unit 2/3 %.





Hope it helps you.
With regards@
Tanisha
Answered by mahaprasad785
18

Answer:

16 whole 2/3

but,

let's see how

Step-by-step explanation:

1) Let the cost price of the purse be ₹x. Then,

Loss = 1/6 of ₹x

= ₹x/6

Cost Price = Selling Price + Loss

x = 250 + x/6

x - x/6 = 250

6x - x/6 = 250

5x/6 = 250

x = 250×6/5

x = 300

Hence, the cost price of the purse is ₹300.

2) Loss = Cost Price - Selling Price

= ₹(300-250)

= ₹50

Loss % = Loss/Cost Price × 100

= 50/300 × 100

= 50/3 %

= 16 whole 2/3 %.

I hope that you get it.

thanks for asking. #keep asking

please mark as brainliest if you like it.

Similar questions