Question

! By selling an article for Rs. 240, a man incurs a
loss of 10%. At what price should be sell it,
so that he make a profit of 20%.​

Answer 1

Answer:

320

Step-by-step explanation:

buying cost was 240×(100/90)=266.67

selling cost was 266.67×(120/100)=320

Answer 2

Answer:

320 rupees

Step-by-step explanation:

Given,

The selling price of the article = 240 rupees,

Loss = 10%,

Since,

$\text{loss}\%=\frac{\text{CP-SP}}{\text{CP}}\times 100$

$10=\frac{CP-240}{CP}\times 100$

$\frac{10CP}{100}=CP-240$

$0.1CP = CP - 240$

$CP - 0.1CP = 240$

$0.9CP = 240$

$\implies CP=\frac{2400}{9}=\frac{800}{3}$

Now, let profit = 20%,

$\text{Profit}\%=\frac{\text{SP-CP}}{\text{CP}}\times 100$

$20=\frac{SP-\frac{800}{3}}{\frac{800}{3}}\times 100$

$0.20 = \frac{\frac{3SP-800}{3}}{\frac{800}{3}}$

$0.20 = \frac{3SP-800}{800}$

$160 = 3SP - 800$

$960 = 3SP$

$\implies SP = 320$

Hence, the selling price would be 320 rupees.