Question

By selling two transistors for Rs 600 each, a shopkeeper gains 20% on one transistor and loses
20% on other.
Find C.P of each transistor.​

Answer 1

400

Step-by-step explanation:

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Answer 2

❃ $Selling \: price \: of \: 1st \: transitor = \: rs \: 600$

$gain\% = 20\%$

$celling \: price = Sp \times 100 \div 100 + gain\%$

$600 \times 100 \div 100 + 20\%$

$60000 \div 120$

$cost \: price \: of \: 1st \: transitor = rs \: 500$

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❃ $selling \: price \: of \: 2nd \: transitor = rs \: 600$

$loss = 20\%$

$cost \: price = sp \times 100 \div 100 - loss\%$

$600 \times 100 \div 100 - 20\%$

$60000 \div 80$

$cost \: price \: of \: second \: transitor = rs \: 750$

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Important Formulae:-

Profit= S.P-C.P

Loss= C.P-S.P

Profit%= Profit÷C.P×100

Loss%= Loss÷C.P×100

Selling price if loss is given= 100+P%÷100×C.P

Selling price if profit is given= 100-L%÷100×C.P

Cost price of loss is given= 100×S.P÷100+P%

Cost price if profit is given= 100×S.P÷100-L%

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