by splitting up the middle term 9x^2-2x-1/3
Answers
Step-by-step explanation:
9x^2-2x-1/3 = 0.
multiply both sides with 3.
3[9x^2-2x-1/3] = 3[0].
=》27x^2-6x-1 = 0.
The first term is, 27x2 its coefficient is 27 .
The middle term is, -6x its coefficient is -6 .
The last term, "the constant", is -1
Step-1 : Multiply the coefficient of the first term by the constant 27 • -1 = -27
Step-2 : Find two factors of -27 whose sum equals the coefficient of the middle term, which is -6 .
-9 + 3 = -6.
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 3
27x2 - 9x + 3x - 1
Step-4 : Add up the first 2 terms, pulling out like factors :
9x • (3x-1)
Add up the last 2 terms, pulling out common factors :
1 • (3x-1)
Step-5 : Add up the four terms of step 4 :
(9x+1) • (3x-1)
Which is the desired factorization.
9x+1 = 0 (or) 3x-1 = 0.
9x= -1 (or) 3x= 1.
x = -1/9 (or) x= 1/3.
therefore x = -1/9 (or) x= 1/3 are the zeroes of the 9x^2-2x-1/3 = 0.
9x^2-3x+x-1/3
3x(3x-1)+3x-1
3x(3x-1)+1(3x-1)
(3x-1)(3x-1)
(3x-1)^2
(3x-1)(3x+1)