Question

by substitution method 6 x minus 2 Y + 10 equal to zero 2 x minus y + 9 = 0 class 10th​

Answer 1

Given equations

$6x-2y+10 = 0\\\implies 6x-2y = -10\\\implies 6x = -10 + 2y\\\implies 3x = -5 + y\\\implies y = 3x+5 --(1)$

$2x-y + 9 = 0\\\implies -y = -9-2x\\\implies y = 9 + 2x -- (2)$

Solving, we get,

$3x+5=9+2x\\3x-2x=9-5\\x=4$

$\implies y = 9 + 2(4) = 9 + 8 = 17$

$\boxed{\boxed{\bold{Therefore. \ the \ values \ of \ x \ and \ y \ are \ 4 \ and \ 17 \ respectively.}}}}$

                                                           

Answer 2

Given:-

→6x-2y+10=0–(1)

→2x-y+9=0–(2)

$\rule{200}{1}$

To Find:-

→The Value of x and y using Substitution method?

$\rule{200}{1}$

AnsWer:-

•Using (2)•

→2x-y+9=0

→2x-y=-9

→2x=9+y

→x=$\frac{9+y}{2}$–(3)

★Using (3) in (1)★

→$\cancel{6}$ ×( $\frac{9+y}{\cancel{2}}$)-2y+10=0

→3×(9+y)-2y=-10

→27+3y-2y=-10

→y=-10-27

→y=-37–(4)

♦Using (4) in (3)♦

→x=$\frac{9+(-37)}{2}$

→x=$\frac{\cancel{-28}}{\cancel{2}}$

→x=-14

∆.Hence,x=-14 and y=-37∆

$\rule{200}{1}$