Question

by The sum of the digits of a two digit number is
14. If the number formed by reversing the
digits is less than the original number for by
18. Find the original numbers.​

Answer 1

Answer:

86 is the answer

Step-by-step explanation:

8+6=14

86-68=18

Answer 2

$\bf{\underline{\underline{Question:-}}}$

The sum of 2 digits is 14. If the number formed by reversing the digits is 18 less than the original number, what is the original number?

$\bf{\underline{\underline{Solution:-}}}$

Let

• the two digits of two digit number be
• tens digit x
• once digit y.

$\bf{\underline{\underline{According\:To\: Question:-}}}$

→ x + y = 14

→ x = 14 - y____equ(¡)

• The number formed is 10x + y

• If the number formed by reversing the digits is 18 less than the original number, what is the original number

• On reversing the digit the number will be 10y + x

→ 10y + x + 18 = (10x + y)

→ 10y + x = 10x + y - 18

→ 10y - y + x - 10x = - 18

→ 9y - 9x = -18_____equ(¡¡)

• Now substituting the value of x from equ(¡) to equ(¡¡)

→ 9y - 9 (14 - y) = - 18

→ 9y - 126 + 9y = - 18

→ 18y = 126 - 18

→ 18y = 108

→ y = 108/18

→ y = 6

$\bf{\underline{\underline{Thus:-}}}$

• once digit if the number is 6

• Substituting value of y in equ(¡)

→ x = 14 - y

→ x = 14 - 6

→ x = 8

$\bf{\underline{\underline{Hence:-}}}$

• The tens digit if two digit number is 8.

• The original number formed is 86.