By travelling at 1/4 of my usual speed,I reach my office 1 hour late.Find my usual time.
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QUESTION --- By travelling at 1/4 of my usual speed,I reach my office 1 hour late.Find my usual time.
ANSWER -----
Let the usual speed be x km/hr
And time taken be y hours
The distance between office and home will be constant i.e. d
d = x × y
d = x/4 × (y+1)
Combining above two equations :
=> xy = x/4 × (y+1)
=> xy = xy/4 + x/4
=> xy × 4/xy = x/4
xy will be cancelled
=> x = 16
Actual Speed = 16 km/hr
==============================
Putting x = 16
x/4 (y+1) = xy
16/4 (y+1) = 16y
4y + 4 = 16y
12y = 4
y = 1/3
>>>>>>>>>>>>>>>>>>>>>>
ANSWER
= ACTUAL TIME = 1/3 Hours OR 20 mins.
>>>>>>>>>>>>>>>>>>>>>
HOPE IT HELPS :):):):):):)
ANSWER -----
Let the usual speed be x km/hr
And time taken be y hours
The distance between office and home will be constant i.e. d
d = x × y
d = x/4 × (y+1)
Combining above two equations :
=> xy = x/4 × (y+1)
=> xy = xy/4 + x/4
=> xy × 4/xy = x/4
xy will be cancelled
=> x = 16
Actual Speed = 16 km/hr
==============================
Putting x = 16
x/4 (y+1) = xy
16/4 (y+1) = 16y
4y + 4 = 16y
12y = 4
y = 1/3
>>>>>>>>>>>>>>>>>>>>>>
ANSWER
= ACTUAL TIME = 1/3 Hours OR 20 mins.
>>>>>>>>>>>>>>>>>>>>>
HOPE IT HELPS :):):):):):)
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