Question

By using eucilds division leema any positve cube integer 11q,11q+6,11q+8

Answer 1

Answer:

Step-by-step explanation:

let a be any positive integer such that a=bq+r where b=11

then a=11b+r , [0≤r<b]

case 1: when r=0

a=11q+0

cubing on both the sides

a³=1331

  =11m , where m= 121q

similarly prove the other cases.