By using factor theorem, factorise 2x³-3x²-17x+30
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=> (x - 2) (2x² + x - 15) = 0
=> (x - 2) (2x² + 6x - 5x - 15) = 0
=> (x - 2) [2x(x + 3) - 5(x + 3)] = 0
=> (x - 2) (2x - 5) (x + 3) = 0
• x - 2 = 0
=> x = 2
• 2x - 5 = 0
=> 2x = 5
=> x =
• x + 3 = 0
=> x = - 3
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