By using factor theorem, factorize the polynomial x^3 + 13x^2 + 32x + 20.
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Answered by
6
X³ + 13x² + 32x + 20
x³ + 12x² + x² + 12x + 20x + 20
x² ( x + 1 ) + 12x ( x + 1 ) + 20 ( x + 1 )
( x + 1 ) ( x² + 12x + 20 )
( x + 1 ) ( x² + 2x + 10x + 20 )
( x + 1 ) [ x ( x + 2 ) + 10 ( x + 2 ) ]
( x + 1 ) [ ( x + 2 ) ( x + 10 ) ]
( x + 1 ) ( x + 2 ) ( x + 10 )
x³ + 12x² + x² + 12x + 20x + 20
x² ( x + 1 ) + 12x ( x + 1 ) + 20 ( x + 1 )
( x + 1 ) ( x² + 12x + 20 )
( x + 1 ) ( x² + 2x + 10x + 20 )
( x + 1 ) [ x ( x + 2 ) + 10 ( x + 2 ) ]
( x + 1 ) [ ( x + 2 ) ( x + 10 ) ]
( x + 1 ) ( x + 2 ) ( x + 10 )
Answered by
2
Hey Friends,
_______________________________
x^3+13x^2+32x+20
=x^3+12x^2+x^2+12x+20x+20
=x^2(x+1)+12x(x+1)+20(x+1)
=(x^2+12x+20)(x+1)
=(x+1)(x^2+2x+10x+20)
=(x+1){x(x+2)+10(x+2)}
=(x+1){(x+2)(x+10)}
=(x+1)(x+2)(x+10)
Hope it's help you!!!!
_______________________________
_______________________________
x^3+13x^2+32x+20
=x^3+12x^2+x^2+12x+20x+20
=x^2(x+1)+12x(x+1)+20(x+1)
=(x^2+12x+20)(x+1)
=(x+1)(x^2+2x+10x+20)
=(x+1){x(x+2)+10(x+2)}
=(x+1){(x+2)(x+10)}
=(x+1)(x+2)(x+10)
Hope it's help you!!!!
_______________________________
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