Question

by using factor thoerm factorize x3-2x2-x+2

Answer 1

Answer:

${x}^{3} - 2 {x}^{2 } - x + 2 \\ = {x}^{2} (x - 2) - 1 (x - 1) \\ = ( {x}^{2} - 1)(x - 1)$

Answer 2

let f( x) =

$x {}^{3} - 2x {}^{2} - x + 2$

put x= -1

$- 1 {}^{3} - 2( - 1) {}^{2} - ( - 1) + 2$

it means -1-2+1+2

answer is zero..

it means (x+1) is the factor put x=2

$2 {}^{3} -2( 2 {}^{2} ) - 2 + 2$

8-8-2+2

=0

it means factors are (x+1)&(x-2)