Question

by using fundamental theorem of arithmetic remove the HCF and LCM of 28 ,42, 56 .
please give this answer fast ​

Answer 1

Answer:

Step-by-step explanation:

28=2×2×7

42=2×3×7

56=2×2×2×7

Therefore

HCF is the number which is common in all 3 and the lowest power of them

HCF=2×7=14

LCM is the product of the highest power of all the numbers in the three

LCM=2×2×2×3×7=168