By using remainder theorem show that g(x) is a factor of f(x) given f(x) = x^3 -x^2+11x +69,g(x) =x+3
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g(x)=x+3
x=-3
Putting the value of x in the equation
f(-3)=(-3)³-(-3)²+11(-3)+69
= -27-9-33+69
= -69+69
=0
x=-3
Putting the value of x in the equation
f(-3)=(-3)³-(-3)²+11(-3)+69
= -27-9-33+69
= -69+69
=0
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