Math, asked by ramanjeet12, 9 months ago

by using suitable identity simply (xy-yz)²​

Answers

Answered by aggarwalreena290
1

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 {(xy - yz)}^{2}

 {(x y})^{2} +  {(yz)}^{2}  - 2 \times xy \times yz

 {x}^{2}  {y}^{2}  +  {y}^{2}  {z}^{2}  - 2xzy^2

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Answered by namitareliable
0

Answer:

using (a-b) ²

(xy-yz)²=(xy)²-2(xy)(yz) +(yz)²

           = x²y²-2xy²z+ y²z²

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