Question

by using the formula solve the quadratic equation x^2-2x+1=0

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given :-

${x}^{2} - 2x + 1 = 0$

Here a = 1 ; b = -2 ; c = 1

Solution :-

we know that, formula for finding the zeroes of the Quadratic equation is

$\frac{ - b \frac{ + }{ - } \sqrt{ {b}^{2} - 4ac} }{2a}$

Substituting the values , we get

$\frac{ - ( - 2) \frac{ + }{ - } \sqrt{ {( - 2)}^{2} - 4 \times 1 \times 1} }{2 \times 1}$

$\frac{2 \frac{ + }{ - } \sqrt{4 - 4} }{2}$

$\frac{2 \frac{ + }{ - } \sqrt{0} }{2}$

$\frac{2 + 0}{2} \: or \: \frac{2 - 0}{2}$

$\frac{2}{2} = 1 \: or \: \frac{2}{2} = 1$

Therefore the zeroes of the Quadratic equation is 1 and 1

• I hope it helps you......✌️✌️✌️