By vector method, provethat sin(a-b)= sina.cosb - cosa.sinb where a,b belong to (0,pi)
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Sin ( A - B) = O/H = ST/1 = ST
ST = PR - PQ
QR = ST
Sin (B) = O/H = PS/1 = PS
Cos (B) = A/H = OP/1 = OP
Sin (A) = O/H = PR / Cos(B)
Sin (A) cos(B) = PR
cos(A) = A/H = PQ/Sin (B)
Cos(A) sin(B) = PQ
ST = PR - PQ
Sin (A-B)
= sin(A) cos(B) - cos(A) sin (B)
If there is any confusion please leave a comment below.
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