Question

By walking at 200/3of his usual speed, a man reaches his office 20 minutes later than usual . his usual time is :

Answer 1

Step-by-step explanation:

I think it's 2/3 rd of the usual speed

Since the distance is const, the time required will be inversely proportional to speed

Let S1 and S2 are the speeds with which he walks and T1 and T2 be the respective time taken

Then S1/S2=T2/T1

Given S2=2/3 S1

Therefore

S1/S2=3/2=T2/T1

T2:T1=3:2

T2=3 UNITS

T2=3 UNITS T1=2 UNITS

T2=3 UNITS T1=2 UNITS T2-T1 = 1UNIT=20 MINUTES

T2=3UNITS=3*20=60MINUTES

USUAL TIME =T1=2UNITS=40 MINUTES

HOPE IT HELPS YOU...