By what factor does the average velocity of a gaseous moecule increase when the temperature (in kelvin) is doubled
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⭐️⭐️⭐️ ANSWER ⭐️⭐️⭐️
⏩⏩ average velocity = √8Rt/πM
average velocity is directly proportional to the root of temperature
average velocity after/ average velocity before = √2T/T = √2 = 1.4
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⭐️⭐️⭐️ ANSWER ⭐️⭐️⭐️
⏩⏩ average velocity = √8Rt/πM
average velocity is directly proportional to the root of temperature
average velocity after/ average velocity before = √2T/T = √2 = 1.4
✨ hOpE iT heLpS ❗️❗️
Answered by
8
avg.velocity=√[8RT÷πM]
hence
v increases by √2 =1.414
thanks me Later ❤️
hence
v increases by √2 =1.414
thanks me Later ❤️
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