Question

By what factor would power of a resistor increase if the current through it increases by a factor of 2 and resistance is halved?​

Answer 1

Answer:

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Answer 2

Answer:

P= I² R

where P= power,

           I= current,

           R= resistance

Given , current increases by a factor of 2, resistance is halved.

( Please note that if anything increases by a factor of n, it is multiplied by n and if it decreases by a factor of n, it is divided by n.)

Therefore, I₂ = 2I, R₂= R/2, P₂ = ?

P₂= (I₂)² R₂

P₂= 4I² (R/2)

P₂= 2I² R = 2 P

Therefore, power increases by a factor of 2.