by what no. should (-3/2) to the power -3 be divided so that the quotient may be (4/27) to the power -2 ? plz hurrry up
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(-3/2) ^ -3 / x = (4/27) ^-2
x/ (-3/2) ^ 3 = (2^2/3^3) ^-2
x = (3^6 / 2^4) * (-3^3/2^3)
x = -( 3^6 *3^3) / 2^7)
x = -(3^9 /2^7)
x/ (-3/2) ^ 3 = (2^2/3^3) ^-2
x = (3^6 / 2^4) * (-3^3/2^3)
x = -( 3^6 *3^3) / 2^7)
x = -(3^9 /2^7)
mkavyashree2004:
thanks
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