By what no. should 3 to the power -2 be divided to get 9 to the power -3.
Please solve this question quickly and with every step.
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3^-2
&
9^-3
=(3^2)^-3
=3^-6
let 3^-2 be divided by x to get 9^-3
3^-2 ÷ x = 9^-3
3^-2/x = 3^-6
x=3^-2 / 3^-6
=3 ^{-2-(-6)}
=3^(-2+6)
=3^4
So the required number is 3^4 or 81.
HOPE IT HELPS..... :-)
&
9^-3
=(3^2)^-3
=3^-6
let 3^-2 be divided by x to get 9^-3
3^-2 ÷ x = 9^-3
3^-2/x = 3^-6
x=3^-2 / 3^-6
=3 ^{-2-(-6)}
=3^(-2+6)
=3^4
So the required number is 3^4 or 81.
HOPE IT HELPS..... :-)
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