By what number should (-3/2)to the power -3 be dived so that the quotient may be (-8/27)to the power -2
Answers
Answered by
0
Hey
(-3/2) ^ -3
(-8/27) ^ -2
We know that a^-n = 1/a^n
In the same way
(-3/2) ^ -3 = 1/(-3/2)^3 = (2/-3)^3 = 8/-27
(-8/27) ^ -2 = 1/(-8/27)^2 = (27/-8)^2 = 729/64
Dividend = divisor × quotient + remainder
Here dividend = -8/27
Quotient = 729/64
Remainder = 0
-8/27 = Divisor × 729/64
(-8/27) ÷ (729/64) = Divisor
(-8/27) × (64/729) = divisor
- 512/19683 = divisor
(-3/2) ^ -3
(-8/27) ^ -2
We know that a^-n = 1/a^n
In the same way
(-3/2) ^ -3 = 1/(-3/2)^3 = (2/-3)^3 = 8/-27
(-8/27) ^ -2 = 1/(-8/27)^2 = (27/-8)^2 = 729/64
Dividend = divisor × quotient + remainder
Here dividend = -8/27
Quotient = 729/64
Remainder = 0
-8/27 = Divisor × 729/64
(-8/27) ÷ (729/64) = Divisor
(-8/27) × (64/729) = divisor
- 512/19683 = divisor
UdayGCGC:
yes this is true. better you take -8/27 as x and use x/x^_2=x3 to make it little easy to calculate
Similar questions