Math, asked by Adityamishra1, 1 year ago

By what number should (-3/2)to the power -3 be dived so that the quotient may be (-8/27)to the power -2

Answers

Answered by wvaish
0
Hey

(-3/2) ^ -3

(-8/27) ^ -2

We know that a^-n = 1/a^n

In the same way

(-3/2) ^ -3 = 1/(-3/2)^3 = (2/-3)^3 = 8/-27

(-8/27) ^ -2 = 1/(-8/27)^2 = (27/-8)^2 = 729/64


Dividend = divisor × quotient + remainder

Here dividend = -8/27

Quotient = 729/64

Remainder = 0

-8/27 = Divisor × 729/64

(-8/27) ÷ (729/64) = Divisor

(-8/27) × (64/729) = divisor

- 512/19683 = divisor


UdayGCGC: yes this is true. better you take -8/27 as x and use x/x^_2=x3 to make it little easy to calculate
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