Question

by what number should (5/3)^-2 be multiplied so that the product may be (7/3)^-1​

Answer 1

(5/3)−2 should be multiplied by 25/21 to obtain (7/3)−1.

Answer 2

Let the required number be 'x'.

${ (\frac{5}{3} )}^{ - 2} \times x = { (\frac{7}{3}) }^{ - 1}$

${ (\frac{3}{5}) }^{ 2} \times x = {( \frac{3}{7}) }^{1}$

$\frac{9}{25} \times x = \frac{3}{7}$

$x = \frac{3}{7} \times \frac{25}{9}$

$x = \frac{25}{21}$

Hope it helps..