By what number should (-5/7) ^3 be divided so that the quotient may be (5/7) ^-2
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Let the numbers be x and y.
We know that Dividend = Divisor × Quotient + Remainder
As per the statement, "If the sum of two numbers is divided by 15, the quotient is 2 and the
remainder is 10 , we get x+y=15×2+10=>x+y=40 --- (1)
Also, as the difference of the same numbers is divided by 3
then the quotient is 4 and the remainder is 2, we get x−y=3×4+2=>x−y=14 --- (2)
Adding
equations 1 and 2, we get 2x=54=>x=27
Substituting
x=27 in the equation (1), we get 27+y=40=>y=13
Thus the numbers are 27,13
Step-by-step explanation:
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