Math, asked by marwansnoopy298, 3 months ago

By what number should be each of the following number be multiplied to get a perfect square in each case? Also find the number whose square is the new number



A 56700

Answers

Answered by Unknown7umit
0

Answer:

this is the answer

Correct option is A)

We are going to find prime factors of 4056

4056=2×2028

=2×2×1014

=2×2×2×507

=2×2×2×3×169

=2×2×2×3×13×13

Now, we are going to make a group of equal number.

=(2×2)×(13×13)×2×3

By observation, 2 and 3 prime factor left out.

So, multiply by 6 we get,

4056×6 =(2×2)×(13×13)×(2×2)(3×3)

24336=(2×2×3×13)×(2×2×3×13)

=(156)×(156)

=(156)

2

∴ To make perfect square we have to multiplied 4056 by 6.

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