by what percent will the gravitational force between the two bodies be increased if their masses are increased by 50%
Answers
Answered by
639
F = Gm1m2/r^2
m1'= m1 + (50/100)m1 = 3m1/2
m2' = m2 +(50/100)m2 = 3m2/2
F' = Gm1'×m2'/r^2
= G ×(3m1/2)×(3m2/2) /r^2
= G×3×m1×3×m2/(r^2)×2×2
= 9/4 × (Gm1m2/r^2)
F' = 9/4 × F
% change = (F'-F)/F × 100
= (9F/4 - F)/F × 100
= (5F/4)/F × 100
= 5/4 × 100
= 125%
Hence the gravitational force will increase by 125%.
hope this helped to you,
plzzz mark as brainliest.......
m1'= m1 + (50/100)m1 = 3m1/2
m2' = m2 +(50/100)m2 = 3m2/2
F' = Gm1'×m2'/r^2
= G ×(3m1/2)×(3m2/2) /r^2
= G×3×m1×3×m2/(r^2)×2×2
= 9/4 × (Gm1m2/r^2)
F' = 9/4 × F
% change = (F'-F)/F × 100
= (9F/4 - F)/F × 100
= (5F/4)/F × 100
= 5/4 × 100
= 125%
Hence the gravitational force will increase by 125%.
hope this helped to you,
plzzz mark as brainliest.......
SARDARshubham:
thanx..........
ur answer is wrong as 3×3=9
oh
ys
now i corrected it, thanx
thanku
from my side
u solve me
that que
ok I got it what I said was the new increased force and the difference will be 225-100 ya it's right 125 is correct
Answered by
65
Hey! Here is the answer
F = Gm1m2/r^2
m1'= m1 + (50/100)m1 = 3m1/2
m2' = m2 +(50/100)m2 = 3m2/2
F' = Gm1'×m2'/r^2
= G ×(3m1/2)×(3m2/2) /r^2
= G×3×m1×3×m2/(r^2)×2×2
= 9/4 × (Gm1m2/r^2)
F' = 9/4 × F
% change = (F'-F)/F × 100
= (9F/4 - F)/F × 100
= (5F/4)/F × 100
= 5/4 × 100
= 125%
Hence the gravitational force will increase by 125%.
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