Chemistry, asked by shamesh, 1 year ago

By Wurtz reaction, a mixture of methyliodide and ethyliodide gives

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Answered by lajpat
16
By Wurtz reaction, (d) a mixture of above three will be obtained.

2methyliodide + 2Na gives ethane.

2ethyliodide +2Na gives butane.

But, methyliodide + ethyliodide +2Na gives propane.
Answered by aryansuts01
0

Answer:

Concept:

Ethyl iodide is a flammable, colourless chemical molecule. It is made by heating ethanol with iodine and phosphorus and has the chemical formula C2H5I. It decomposes when exposed to air, especially when exposed to sunshine, and turns yellow or reddish due to dissolved iodine. It's also possible to make it by mixing hydroiodic acid with ethanol and then evaporating the resulting ethyl iodide. Iodomethane, also known as methyl iodide and abbreviated "MeI," is a chemical compound with the formula CH3I. It's a viscous, colourless liquid that's extremely combustible. Although one hydrogen atom is substituted with an iodine atom, it has a chemical structure similar to methane. Rice plants naturally produce a little amount of it.

Given:

A combination of methyliodide and ethyliodide produces methyliodide and ethyliodide by the Wurtz reaction.

option [A] Propane

option [B] Ethane

option [C] Butane

option [D] A mixture of above three

Find:

choose the best answer to the provided question

Answer:

When sodium in ethereal solution is added to methyl iodide and ethyl iodide, a combination of propane, ethane, and butane is formed. This process can produce all-butane, ethane, and propane. Alkanes are generated when halogens react with potassium in the environment of anhydrous ether. Wurtz's response is the name given to this reaction.

CH_{3} Br+2Na+BrCH_{3}  - > CH_{3} .CH_{3} +2NaBr

When salt is added to methyl iodide and ethyl iodide in ethereal solution, a combination of methane, ethane, and butane is formed.

CH_{3} -CH_{2} -I+CH_{3} -I+2Na- > CH_{3} -CH_{2}-CH_{3}+2NaI [propane]

CH_{3}I+2Na+I-CH_{3}- > CH_{3}-CH_{3}+NaI [ethane]

C_{2} H_{5} I+2Na+I-C_{2}H_{5}  - > C_{2}H_{5} -C_{2}H_{5} +2NaI [butane]

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