C
1.
Р
In the following figure, AOB is a straight angle. OQ
is the bisector of AOC and OP is the bisector of BOC.
B
O
If AOC = 60°, then find i) BOC ii) POQ.
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In figure 11, OP bisects ∠AOC, OQ bisects ∠BOC and OP⊥OQ. Show that the points A,O and B are collinear.
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ANSWER
Given:
OP bisects ∠AOC, OQ bisects ∠BOC and OP⊥OQ
To prove: The points A,O and B are collinear.
Proof:
Since, OP bisects ∠AOC,
∠AOP=∠COP …… (1)
Since, OQ bisects ∠BOC,
∠BOQ=∠COQ …… (2)
Now, ∠AOB
=∠AOP+∠COP+∠COQ+∠BOQ
=∠COP+∠COP+∠COQ+∠COQ
From (1) and (2), we have
=2(∠COP+∠COQ)
=2∠POQ
=2(90
∘
)
=180
∘
Therefore, points A,O and B are collinear.
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