C 14. If b cos B = c cos C, then the triangle is :
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True
For any triangle ,
From cosine rule ,
cosA=2bcb2+c2−a2
acosA=a2bcb2+c2−a2
cosB=2aca2+c2−b2
bcosA=b2aca2+c2−b2
⟹b2aca2+c2−b2=a2bcb2+c2−a2a2b2+b2c2−b4=a2b2+a2c2−a4b2c2−
Step-by-step explanation:
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