Question

(C) 1932
(D) 1776
Two angles of a quadrilateral are 36%
and 90° and the remaining two angles
differ by 18". Find the ratio of the
smallest angle to the largest angle of
the quadrilateral.
A) 1:3
(B) 3:7
C) 2:9
(D) 2:7​

Answer 1

Answer:

vjvhvjgvjvgkjjvjvjgjvjvjfhjvufhvjfgjgihnnb

Step-by-step explanation:

i dont now

Answer 2

Answer:

see as we all know that sum of all angles o of a quadrilateral is 360°

now let the other two angles be x and y.

therefore,

90°+36°+x+y=360°

x+y=360°-126°

x+y=234°

....

Hence u got two equation i.e

x-y=18° ( given ). -(1)

x+y=234°. -(2)

Now,

subtracting equation (1) and (2) we get,

x-y - (x+y) = 18° - 234°

x-y-x-y = -216°

-2y = -216

y=216/2

y=108°

substituting this value of y in equation (1) we get

x-108=18

x=18+108

x=126°

Since the smallest angle we found is 36° and the largest angle we found is 126°

Hence , finding the ratio of the smallest angle to the largest angle of the quadrilateral...

36°/126°

we get 2:7.

HENCE THE ANSWER IS 2:7.