Math, asked by hermione12361, 1 year ago

c^2=√a^2-b^2
solve for c​

Answers

Answered by charliejaguars2002
9

Answer:

\large\boxed{c=\sqrt{a-b^2},c=-\sqrt{a-b^2}  }

Step-by-step explanation:

To solve this problem, first you have to find the value of c. Isolate by the c on one side of the equation. You have to use radical rule and exponent rule.

Given:

c²=√a²-b²

Solutions:

First, use radical rule.

\large\boxed{\textnormal{RADICAL RULE}}

\displaystyle \sqrt{D}=D^\frac{1}{2}

\displaystyle a(\frac{1}{2})^2

\large\boxed{\textnormal{EXPONENT RULE}}}

\displaystyle (a^b)^c=a^b^c

\displaystyle A^\frac{1}{2}^*^2

Multiply numbers from left to right.

\displaystyle \frac{1}{2}*2

\displaystyle \frac{1*2}{2}=\frac{2}{2}=1

\displaystyle=a

Rewrite the whole problem down. (Refine.)

\displaystyle c^2=a-b^2

Solve.

\large\boxed{c=\sqrt{a-b^2},c=-\sqrt{a-b^2}}

In conclusion, the correct answer is c=√a-b² & c=-√a-b².

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