Question

(C) 2
The smallest number which
when divided by 5, 10, 12 ans
15, leaves remainder 2 inch
case, but when did by
leaves no remainder
(a) 189
(b) 190
(c) 175
What least nu​

Answer 1

Answer:

60 is the LCM of the numbers. Let X be the number which when divides the least number leaves zero remainder.

The least number is 60k + 2

so (60k+2)/X this value is divisible by X

now I don't know what X is.

your question is incomplete.

Let X be 7 then (60k+2) is divisible by 7

so it can be written as 56k + 4k +2 because 56 is divisible by 7 now find a value of k for which 4k+2 is divisible by 7. k=3 can solve the problem. 4*3+2=14 which is also divisible by 7.

so incase X=7 the least number will be 60*3+2 =182

I know it doesn't match the options, but depending upon your value of X you can find the exact answer.

Hope it helps!