c. √3x^2 - 2√2x - 2√3 = 0
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Answered by
3
Answer:
Heya !!
The given equation is √3X² - 2√2X - 2√3 = 0
Here,
a = √3 , b = -2√2 and c = -2√3.
Discriminant ( D ) = B²-4AC
=> (-2√2)² - 4 × √3 × -2√3
=> 8 + 24
=> 32
✓D = √32 = √2 × 2 × 2 × 2 × 2 = 4√2.
Roots of the given equation are : -B + √D/2A and -B - √D/2A
=> - (-2✓2) + 4√2 / 2√3 and -(-2√2) - 4√2/2√3
=> ( 2√2 + 4√2 ) /2√3 and (2√2 - 4√2 ) /2√3
=> ( 6√2/2√3 ) And ( -2√2/2√3 ).
=> ( 3√2/√3 ) and ( -√2/√3)
=> ( √3 × √3 × √2/✓3) and ( -√2/√3)
=> ( √3 × √2 ) and ( -√2/✓3)
=> ( √6 ) and ( -√2/√3).
Mark as the brainliest please
Answered by
0
The given equation is √3X² - 2√2X - 2√3 = 0
Here,
a = √3 , b = -2√2 and c = -2√3.
Discriminant ( D ) = B²-4AC
=> (-2√2)² - 4 × √3 × -2√3
=> 8 + 24
=> 32
✓D = √32 = √2 × 2 × 2 × 2 × 2 = 4√2.
Roots of the given equation are : -B + √D/2A and -B - √D/2A
=> - (-2✓2) + 4√2 / 2√3 and -(-2√2) - 4√2/2√3
=> ( 2√2 + 4√2 ) /2√3 and (2√2 - 4√2 ) /2√3
=> ( 6√2/2√3 ) And ( -2√2/2√3 ).
=> ( 3√2/√3 ) and ( -√2/√3)
=> ( √3 × √3 × √2/✓3) and ( -√2/√3)
=> ( √3 × √2 ) and ( -√2/✓3)
=> ( √6 ) and ( -√2/√3).
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