Question

c) 4 x ² - 4x + 1 factorise
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Answer 1

${} \huge \red{Answer - }$

$4 {x}^{2} - 4x + 1 \\ = 4 {x}^{2} - (2 + 2)x + 1 \\ = 4 {x}^{2} - 2x - 2x + 1 \\ = 2x(2x - 1) - 1(2x - 1) \\ = (2x - 1)(2x - 1)$

Answer 2

$4 {x}^{2} - 4x + 1 \\ 4 {x}^{2} - 2x - 2x + 1 \\ 2x(2x - 1) - 1(2x - 1) \\ (2x - 1)(2x - 1)$

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