C --- (a) D 1200 90° 90° A B.
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We know, by angle sum property, the sum of angles of a quadrilateral is 360o.
The given angles are, 75o,90o,75o.
Let the fourth angle be xo.
Then, 75o+90o+75o+xo=360o.
⇒ 360o−(75o+90o+75o)=x∘
⇒ xo=360o−240o=120∘.
Therefore, the fourth angle is xo=120o.
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